This article is a barebone introduction. I don't present any mathematics here, only lots of diagrams and animations. The other articles on this site do have the math content to prove the statements that are made. Here you'll have to take my word for it.
The Coriolis effect in Meteorology
On this page I discuss the rotation-of-Earth-effect that is taken into account in Meteorology, where it is referred to as 'the Coriolis effect'. (For the rotation of Earth effect that applies in ballistics, see the following two Java simulations: Great circles and Ballistics).
The first consequence of the fact that the Earth is rotating is that it's not a perfect sphere; there is an equatorial bulge. The Earth has been molded to the same shape as a completely liquid planet would have. The bulge is small; on Earth pictures taken from outer space you can't see it. It may seem unimportant but it's not: what matters for meteorology is an effect that arises from the Earth's rotation and the resulting oblateness together.
A model: parabolic dish
Thinking about motion over the Earth's surface is rather complicated, so I turn now to a model that is simpler but still presents the feature that gives rise to the Coriolis effect.
The dish in the picture is a bit deeper in the center than on the outside. It was manufactured as follows: a flat platform with a rim was rotating at a very constant angular velocity (10 revolutions per minute), and a synthetic resin was poured onto the platform. Being liquid the resin redistributed itself, covering the entire area. The resin had enough time to reach an equilibrium state before it started to set. The end state is an equilibrium between the tendency to flow outwards and push up and the tendency of gravity to make the surface of a fluid a level surface. The surface was sanded to a very smooth finish.
Also, note the construction that is hanging over the parabolic dish. The vertical rod is not attached to the table but to the dish; when the dish rotates the rod rotates with it. The overhanging construction carries a video camera so the footage from that camera will show the motion as seen from a co-rotating point of view.
It can be shown mathematically that the cross-section of the resulting surface is a parabola. Here is how that parabolic dish serves as a model for the rotating Earth: If you would pour water out on the dish (while it is rotating at the same 10 revolutions per minute) then the distribution of that water comes out the same as it did when the resin redistributed. So there will be an even thickness of water everywhere
The natural shape of a water surface is to be flat. Due to the rotation the water surface assumes a parabolic shape.
The natural shape of a planet is to be spherical. Due to the rotation the Earth assumes an oblate shape, with the planet's water as a layer on it that is a couple of kilometers thick. Incidentally, the Earth didn't get to its present oblate shape from a spherical shape. In the beginning of our solar system, when the Earth started to form, it was a protoplanetary disk. Under its self-gravity the protoplanetary disk contracted more and more into a planet. Because of the rotation the contraction did not proceed all the way to a spherical shape.
The parabolic dish is hollow, and the Earth is convex, and recognizing that the parabolic dish models the Earth is not straightforward. The following series of four images is designed to bridge the gap.
Image A shows that if a dish as big as a continent would be placed on the north pole then the Earth's gravity would tend to pull objects on the dish towards the middle.
In Image B the straight line represents a huge perfectly flat disk. Even though it is flat, the fact that the Earth's gravity pulls towards the Earth's center gives all objects on the disk a tendency to move to the middle.
In Image C the line represents a structure that has in common with the previous two examples that objects located on it will tend to move to the middle. Even though the structure is convex, it is effectively a bowl because the outside, the rim, is further away from the Earth's center of gravity than the middle.
Finally, Image D represents the situation on Earth, with its equatorial bulge. Effectively, each hemisphere is a bowl, and the equator is the rim of these bowls.
In both diagrams the blue arrow represent gravity. In the case of the dish it pulls straight down, in the case of the planet it pulls towards the Earth's center.
The red arrow represents what is referred to as 'the normal force'. (Here, the word 'normal' is used in its mathematical sense of being perpendicular.) The surface of the dish carries the water that it contains, which means that the surface exerts a force upon the water, exactly perpendicular to the surface.
(For some remarks about how large the Earth's equatorial bulge is, and how large the inward force is, see the Equatorial bulge discussion on this page.)
Sliding over the parabolic dish
This particular dish doesn't get water poured over it, that would make it too heavy. Instead, for demonstrations small objects, manufactured to have very little friction, are placed on the surface.
In the above animation two perspectives are shown next to each other. On the left the actual motion of the dish, on the right the motion as seen from the overhanging video-camera. On the rim of the disk different shades of grey divide the rim in four quadrants, to show clearly which view is the non-rotating view.
The frictionless object has been placed on the parabolic dish in such a way that it is simply co-rotating with the dish. The dish is rotating with the same angular velocity as when it was manufactured. In that case the inward force arising from the slope is precisely the amount that is required to sustain motion along a circle. If you would place several objects on the rotating dish, all with no velocity relative to the dish, then they would simply keep their positions relative to each other. In that case if you just have the image from the overhanging camera you'd be hard pressed to tell whether you are looking at a rotating assembly or a stationary assembly.
However, when the object has a velocity relative to the rotating dish interesting things happen.
In the above animation an arrow has been added to emphasize that the slope of the surface gives rise to an inward force. Note that near the rim the inward force is stronger. In fact, it is precisely proportional; a property of the parabolic shape is that the inward force arising from the slope is exactly proportional to the distance to the central axis of rotation. From here on I will write 'proportional force' as shorthand for 'a force that is proportional to the distance to the central axis of rotation.'
Compared to the circular motion the frictionless object has been nudged; it has been given a velocity relative to the parabolic dish. Note that on average the object is still co-rotating with the dish, it's just that the circumnavigation is now not circular but ellipse-shaped.
The above animation shows that the motion along the ellipse-shaped trajectory can be seen as a combination of two circles: a main circle and an epi-circle. As seen from a co-rotating view what you see is precisely the motion along the epi-circle.
Rule of motion
The following statement is proved in other articles on this website, here I will just state this rule of motion:
Here is what is important about that rule of motion:
This rule of motion applies both in the case of motion over the surface of the parabolic dish and the case of motion over the Earth's surface.
Cause of the turning
The cause of the turning is different in each direction, but the common factor is that in every direction it's an interplay between the inward force and the inertia of the circumnavigating object.
(You may wonder whether the turning can also be explained with an example that uses motion in a straight line. For an answer see the straight line discussion in the Remarks section. )
Adding pressure gradient force to the picture
The lesson learned from motion on the surface of the parabolic dish can now be applied to motion over the surface of the Earth: the tendency to deflect is equally strong in all directions.
In meteorology, the two main factors affecting motion of winds are pressure gradient force and Coriolis effect. The following pictures represent the formation of flow around a low pressure area.
The blue arrows represent the tendency to flow towards a low pressure area, the red arrows represent the Coriolis effect. The diagrams are very schematic, to bring out the features that are essential.
At the start, air mass, being subject to pressure gradient force, starts flowing from all sides to the low pressure area. All the flows, from the North, the South, the East or the West, etc, get deflected to the right of their initial direction. The overall result of the deflections is that the flows shepherd each other into a flow pattern around the low pressure area. In the end the direction of flow is perpendicular to the pressure gradient.
The flow around the low pressure area is characterized by a sort of tug-of-war between pressure gradient force and Coriolis effect.
And there is another way in which the Coriolis effect remains an active factor: when the overall flow field contracts there is an inward velocity component. Every time some inward velocity component developes the Coriolis effect deflects that velocity component to flow that is once more perpendicular to the pressure gradient. So the Coriolis effect not only fosters the formation of flow around the low pressure area, but it also acts to sustain that flow.
At the equator the Earth's surface is about 20 kilometers further away from the Earth's geometric center than at the poles. Compared to the total Earth radius of 6400 kilometer that looks like a very small difference indeed, you may be tempted to think the bulge is negligable.
In the diagram the angle between the red and the blue arrow is exaggerated for clarity; in the case of the actual Earth that angle, at 45 degrees latitude, is about a tenth of a degree. That downward slope of 0.1 degree provides the required inward force.
At a rate of one revolution per day, how much inward force is required to circumnavigate the Earth's axis? For the latitude of 45 degrees the calculation gives that for an object with a mass of 1 kilogram a force of 1.7 gram-force is required. The ratio is 1:580. So whatever measure of weight you use, divide it by 580 and you have the required inward force.
I weigh about 80 kilogram (176 american pounds), and for me the required force is about 140 gram-force. If you have some weighing utensil at hand, feel how strong you have to push to exert 140 gram-force.
Explanation with motion in a straight line?
Here I discuss whether the turning that is so typical of the rotation-of-Earth-effect can also be explained with an example that is based on motion in a straight line. To do that I will discuss two cases, one with motion over a parabolic dish, and one with motion over a level surface. I will invoke the following as crucial criterium: the rotation-of-Earth-effect that is at play in the atmosphere is the same for all directions of motion.
Imagine you are on a parabolic ice-rink. (That would require a very large platform. Actually, in France there is a scientific center that has a 13 meter diameter rotating tank. When that rotating water mass is in an equilibrium state you can try to freeze it, which would result in a parabolic ice-rink.)
Imagine you are on that ice-rink, co-rotating with it (and the ice-rink is rotating with the same angular velocity as when it was manufactured). You give an ice-hockey puck a push so that goes forward. That is: you push it so that it
still circumnavigates the central axis, but faster than the rink itself. The puck will then start to recede from the central axis.
Now for the same experiment conducted on the surface of a rotating flat disk. The animation below illustrates such a setup. You see several pucks being launched at the same time, all moving along the same straight line, but with different velocities.
The pucks that move in forward direction move away from the central axis. Ok, that is somewhat the same as in the parabolic dish case.
How about the puck that is moving in rearward direction? The rearward moving pucks are receding from the central axis of rotation too! They recede because they are moving along a straight line that is tangent to the circular platform. Hence on a flat disk it doesn't matter whether the pucks are moving forward or rearward, either way they are receding from the central axis of rotation.
The answer to the question is No: in Meteorology the deflection of the motion with respect to the rotating system cannot be explained with a example that is based on motion in a straight line.
Other material on this site
Further discussion of the terrestrial Coriolis effect is in the article Oceanography: Inertial oscillations
Relevant for Meteorology:
Relevant for ballistics:
Last time this page was modified: March 22 2012